9x^2+x+5=36

Solution for 9x^2+x+5=36 equation:

9x^2+x+5=36

We move all terms to the left:

9x^2+x+5-(36)=0

We add all the numbers together, and all the variables

9x^2+x-31=0

a = 9; b = 1; c = -31;
Δ = b2-4ac
Δ = 12-4·9·(-31)
Δ = 1117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1117}}{2*9}=\frac{-1-\sqrt{1117}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1117}}{2*9}=\frac{-1+\sqrt{1117}}{18}
$